问题链接
https://leetcode.cn/problems/best-time-to-buy-and-sell-stock-ii/description/
解题思路
买卖股票,本质上就是低价买入,高价卖出。我们可以用模拟法,不断的去找到一个递增的区间,然后去相加。
但这题还可以用贪心做。贪心是每一天都把收益想成是最大,即只计算眼前。但是,如果每一天都拿到了最大的收益,那这一段区间就能拿到一个整体最优的收益。
代码
模拟法:
class Solution: def maxProfit(self, prices) -> int: idx = 0 res = 0 last_val = prices[0] while idx < len(prices): while idx < len(prices) and last_val >= prices[idx]: last_val = prices[idx] idx += 1 idx -= 1 buy = prices[idx] while idx < len(prices) and last_val <= prices[idx]: last_val = prices[idx] idx += 1 idx -= 1 sail = prices[idx] res += sail-buy idx += 1 return res
贪心法:
class Solution: def maxProfit(self, prices) -> int: res = 0 for i in range(1, len(prices)): res += max(0, prices[i]-prices[i-1]) return res
标签:last,idx,val,res,len,II,122,最佳时机,prices From: https://www.cnblogs.com/bjfu-vth/p/17041584.html