Construct the Rectangle
A web developer needs to know how to design a web page's size. So, given a specific rectangular web page’s area, your job by now is to design a rectangular web page, whose length L and width W satisfy the following requirements:
The area of the rectangular web page you designed must equal to the given target area.
The width W should not be larger than the length L, which means L >= W.
The difference between length L and width W should be as small as possible.
Return an array [L, W] where L and W are the length and width of the web page you designed in sequence.
Example 1:
Input: area = 4
Output: [2,2]
Explanation: The target area is 4, and all the possible ways to construct it are [1,4], [2,2], [4,1].
But according to requirement 2, [1,4] is illegal; according to requirement 3, [4,1] is not optimal compared to [2,2]. So the length L is 2, and the width W is 2.
Example 2:
Input: area = 37
Output: [37,1]
Example 3:
Input: area = 122122
Output: [427,286]
Constraints:
1 <= area <= 107
思路一:遍历 [1, sqrt(n)], 检测是否整除,如果是则符合答案
public int[] constructRectangle(int area) {
int[] result = new int[]{area, 1};
for (int i = 2; i <= Math.sqrt(area); i++) {
if (area % i == 0) {
result[0] = area / i;
result[1] = i;
}
}
return result;
}
标签:web,area,int,page,width,length,easy,leetcode,492
From: https://www.cnblogs.com/iyiluo/p/17023451.html