小米备份文件，可以用7zip打开得到apk
对apk进行分析，跳转到加密代码，通过分析代码，发现只需要最后的md5值和8b9b0ad9c324204fac87ae0fc2c630bd相等即可
同时资源中又发现password必须大于5位
一开始的想法是hook上面的方法，认为通过验证后能拿到flag
脚本如下
setImmediate(function() {
Java.perform(function() {
var targetClass='nep.zxc.catpaw.data.LoginDataSource';
var methodName='login';
var gclass = Java.use(targetClass);
gclass[methodName].overload("java.lang.String").implementation = function(arg0) {
var loginUser = Java.use("nep.zxc.catpaw.data.model.LoggedInUser").$new("12345","admin");
//hook内部类
var resultClass = Java.use("nep.zxc.catpaw.data.Result$Success");
var ret = resultClass.$new(loginUser);
return ret;
}
})
})
hook之后是直接显示通过，并没有给出flag
之后在so中发现读取/dev/input/event1并保存在应用目录下
备份文件中的数据文件就是保存下来的输入数据
利用命令即可模拟输入
一次输入是CatC，大概是因为输入的时候报错了，我的手机并不是小米手机，只是刷了MIUI系统，可能是这个原因导致报错，没有全部输入完成
转换思路，通过阅读文章https://blog.seeflower.dev/archives/45/，发现可以分析文件指令，先通过命令getevent -lt /dev/input/event1和命令cat 1666666666 >> /dev/input/event1可以抓取文件未报错部分的信息
可以看到上图中按下的坐标值，根据坐标值搜索文件的16进制数据，可以发现两个指令，指令03003500代表X轴，指令03003600代表Y轴
依次写出脚本提取所有的坐标
def get_x(v):
x = []
for i in range(4):
tmp = str(hex(v[i+4]))[2:]
if len(tmp) == 1:
tmp = "0" + tmp
x.append(tmp)
x.reverse()
ret = ""
for v in x:
ret += v
return int(ret,16)
def get_y(v):
y = []
for i in range(4):
tmp = str(hex(v[i+4]))[2:]
if len(tmp) == 1:
tmp = "0" + tmp
y.append(tmp)
y.reverse()
ret = ""
for v in y:
ret += v
return int(ret,16)
def is_y(v):
if v[0] == 0x03 and v[1] == 0x00 and v[2] == 0x36 and v[3] == 0x00:
return True
return False
def is_x(v):
if v[0] == 0x03 and v[1] == 0x00 and v[2] == 0x35 and v[3] == 0x00:
return True
return False
with open("1666666666","rb") as fr:
rd = fr.read()
for i in range(16,len(rd),24):
v = rd[i:i+8]
x = 0
y = 0
if is_x(v):
x = get_x(v)
print(x,end=",")
if is_y(v):
y = get_y(v)
print(y)
# 622,319
# 83,1901
# 472,1904
# 81,1892
# 133,1739
# 493,1603
# 62,1892
# 443,502,1601
# 450,1755
# 97,1903
# 107,2064
# 293,1622
# 487,1620
# 635,1751
# 271,1601
# 83,2086
# 1011,1626
# 65,1919
# 453,1913
# 386,1438
# 500,1588
# 84,2021
# 1015,1630
# 87,2074
# 465,1902
# 489,1446
# 90,2042
# 1028,1611
# 77,1897
# 417,1599
# 77,1903
# 286,1613
# 438,1912
# 1032,1491
# 388,1615
# 325,1758
# 804,1623
# 82,1895
# 765,1908
# 920,1464
# 76,2056
# 1016,1635
# 89,2060
# 769,1763
# 431,1912
# 385,1614
# 290,1435
# 1437
# 756,1933
# 95,2051
# 1021,1647
# 648,1906
# 593,1597
# 86,2069
# 1029,1649
# 817,1615
# 767,1899
# 83,1919
# 1043,1643
# 79,1909
# 715,1611
# 492,1625
# 89,2090
# 1040,1632
# 289,1607
# 542,1918
# 81,1935
# 292,1580
# 80,1909
# 756,1922
# 711,1466
# 83,2021
# 392,1605
# 587,781
提取的数据中出现两个问题，可以看到少了两条数据，443没有对应的Y轴，1437没有对应的X轴
干脆先把两者互补一下，都是443,1437，利用adb进行模拟点击
adb shell input tap 622 319 adb shell input tap 83 1901 adb shell input tap 472 1904 adb shell input tap 81 1892 adb shell input tap 133 1739 adb shell input tap 493 1603 adb shell input tap 62 1892 adb shell input tap 443 1437 adb shell input tap 502 1601 adb shell input tap 450 1755 adb shell input tap 97 1903 adb shell input tap 107 2064 adb shell input tap 293 1622 adb shell input tap 487 1620 adb shell input tap 635 1751 adb shell input tap 271 1601 adb shell input tap 83 2086 adb shell input tap 1011 1626 adb shell input tap 65 1919 adb shell input tap 453 1913 adb shell input tap 386 1438 adb shell input tap 500 1588 adb shell input tap 84 2021 adb shell input tap 1015 1630 adb shell input tap 87 2074 adb shell input tap 465 1902 adb shell input tap 489 1446 adb shell input tap 90 2042 adb shell input tap 1028 1611 adb shell input tap 77 1897 adb shell input tap 417 1599 adb shell input tap 77 1903 adb shell input tap 286 1613 adb shell input tap 438 1912 adb shell input tap 1032 1491 adb shell input tap 388 1615 adb shell input tap 325 1758 adb shell input tap 804 1623 adb shell input tap 82 1895 adb shell input tap 765 1908 adb shell input tap 920 1464 adb shell input tap 76 2056 adb shell input tap 1016 1635 adb shell input tap 89 2060 adb shell input tap 769 1763 adb shell input tap 431 1912 adb shell input tap 385 1614 adb shell input tap 290 1435 adb shell input tap 443 1437 adb shell input tap 756 1933 adb shell input tap 95 2051 adb shell input tap 1021 1647 adb shell input tap 648 1906 adb shell input tap 593 1597 adb shell input tap 86 2069 adb shell input tap 1029 1649 adb shell input tap 817 1615 adb shell input tap 767 1899 adb shell input tap 83 1919 adb shell input tap 1043 1643 adb shell input tap 79 1909 adb shell input tap 715 1611 adb shell input tap 492 1625 adb shell input tap 89 2090 adb shell input tap 1040 1632 adb shell input tap 289 1607 adb shell input tap 542 1918 adb shell input tap 81 1935 adb shell input tap 292 1580 adb shell input tap 80 1909 adb shell input tap 756 1922 adb shell input tap 711 1466 adb shell input tap 83 2021 adb shell input tap 392 1605 adb shell input tap 587 781
本次点击的效果如下，很明显不符合flag的形式，其次是443,1437，显示的是5，第一个5显而易见是C，将坐标改成C的坐标即可
然而即使是CatCTF{thepC4T_!5_RecprdiN9_$cr35n"by"inLutpev{N7}，那也很奇怪了，并且md5校验不通过
通过打开安卓的触控指针位置并进行录屏，对每次点击的位置进行分析
利用PotPlayer对视频进行逐帧分析，发现每次点击都在键盘偏下的位置，因此需要减少Y轴的值，通过不断调试，发现减少25最为合适
同时注意到了1437这个没有X坐标的值，这个高度位于数字区，也就是说如果5不正确，最多再试9次，依旧能获得正确的值
修改后代码如下
def get_x(v):
x = []
for i in range(4):
tmp = str(hex(v[i+4]))[2:]
if len(tmp) == 1:
tmp = "0" + tmp
x.append(tmp)
x.reverse()
ret = ""
for v in x:
ret += v
return int(ret,16)
def get_y(v):
y = []
for i in range(4):
tmp = str(hex(v[i+4]))[2:]
if len(tmp) == 1:
tmp = "0" + tmp
y.append(tmp)
y.reverse()
ret = ""
for v in y:
ret += v
return int(ret,16)
def is_y(v):
if v[0] == 0x03 and v[1] == 0x00 and v[2] == 0x36 and v[3] == 0x00:
return True
return False
def is_x(v):
if v[0] == 0x03 and v[1] == 0x00 and v[2] == 0x35 and v[3] == 0x00:
return True
return False
with open("1666666666","rb") as fr:
rd = fr.read()
for i in range(16,len(rd),24):
v = rd[i:i+8]
x = 0
y = 0
if is_x(v):
x = get_x(v)
print(x,end=",")
if is_y(v):
y = get_y(v)
print(y-25)
修改后的脚本如下
adb shell input tap 622 294 adb shell input tap 83 1876 adb shell input tap 472 1879 adb shell input tap 81 1867 adb shell input tap 133 1714 adb shell input tap 493 1578 adb shell input tap 62 1867 adb shell input tap 472 1879 adb shell input tap 502 1576 adb shell input tap 450 1730 adb shell input tap 97 1878 adb shell input tap 107 2039 adb shell input tap 293 1597 adb shell input tap 487 1595 adb shell input tap 635 1726 adb shell input tap 271 1576 adb shell input tap 83 2061 adb shell input tap 1011 1601 adb shell input tap 65 1894 adb shell input tap 453 1888 adb shell input tap 386 1413 adb shell input tap 500 1563 adb shell input tap 84 1996 adb shell input tap 1015 1605 adb shell input tap 87 2049 adb shell input tap 465 1877 adb shell input tap 489 1421 adb shell input tap 90 2017 adb shell input tap 1028 1586 adb shell input tap 77 1872 adb shell input tap 417 1574 adb shell input tap 77 1878 adb shell input tap 286 1588 adb shell input tap 438 1887 adb shell input tap 1032 1466 adb shell input tap 388 1590 adb shell input tap 325 1733 adb shell input tap 804 1598 adb shell input tap 82 1870 adb shell input tap 765 1883 adb shell input tap 920 1439 adb shell input tap 76 2031 adb shell input tap 1016 1610 adb shell input tap 89 2035 adb shell input tap 769 1738 adb shell input tap 431 1887 adb shell input tap 385 1589 adb shell input tap 290 1410 adb shell input tap 443 1412 adb shell input tap 756 1908 adb shell input tap 95 2026 adb shell input tap 1021 1622 adb shell input tap 648 1881 adb shell input tap 593 1572 adb shell input tap 86 2044 adb shell input tap 1029 1624 adb shell input tap 817 1590 adb shell input tap 767 1874 adb shell input tap 83 1894 adb shell input tap 1043 1618 adb shell input tap 79 1884 adb shell input tap 715 1586 adb shell input tap 492 1600 adb shell input tap 89 2065 adb shell input tap 1040 1607 adb shell input tap 289 1582 adb shell input tap 542 1893 adb shell input tap 81 1910 adb shell input tap 292 1555 adb shell input tap 80 1884 adb shell input tap 756 1897 adb shell input tap 711 1441 adb shell input tap 83 1996 adb shell input tap 392 1580 adb shell input tap 587 756
本次运行效果如下，这次就有点像样了，不过这串的md5值还是不匹配
那很简单了，将$cr35n的5用其他数字进行替换，最终在替换为3时，md5值成功匹配
在app中进行验证，成功攻破
结果为CatCTF{the_C4T_!5_Rec0rdiN9_$cr33n_by_inPut_evEn7}