数据结构实验之链表三:链表的逆置
Time Limit: 1000MS Memory Limit: 65536KB
Submit Statistic
Problem Description
输入多个整数,以-1作为结束标志,顺序建立一个带头结点的单链表,之后对该单链表的数据进行逆置,并输出逆置后的单链表数据。
Input
输入多个整数,以-1作为结束标志。
Output
输出逆置后的单链表数据。
Example Input
12 56 4 6 55 15 33 62 -1
Example Output
62 33 15 55 6 4 56 12
#include <stdio.h>
#include <stdlib.h>
#include <malloc.h>
typedef struct node
{
int data;
struct node *next;
}list;
int main()
{
list *p,*head;
head = (list *)malloc(sizeof(list));
head->next = NULL;
int n;
while(scanf("%d",&n)!=EOF)
{
if(n==-1)
{
break;
}
else
{
p = (list *)malloc(sizeof(list));
p->data = n;
p->next = head->next;
head->next = p;
}
}
p = head->next;
while(p)
{
if(p->next!=NULL)
{
printf("%d ",p->data);
}
else
{
printf("%d\n",p->data);
}
p=p->next;
}
return 0;
}
只允许蒋文文转载。
#include <stdio.h>
#include <malloc.h>
#include <stdlib.h>
typedef struct LNode{
int data;
struct LNode *next;
}*LinkList,LNode;
LinkList createLinkList(LinkList &head){
LNode *tail,*p;
head =tail = (LinkList)malloc(sizeof(LNode));
head->next = NULL;
tail = head;
tail->next = NULL;
int data=0;
scanf("%d",&data);
do
{
p = (LinkList)malloc(sizeof(LNode));
p->next = NULL;
p->data = data;
p->next = tail->next; //顺序不能错
tail->next = p;
scanf("%d",&data);
}while(data!=-1);
return head;
}
void display(LinkList p){
p=p->next;
while(p){
if (p->next)
{
printf("%d ",p->data);
}else{
printf("%d\n",p->data);
}
p = p->next;
}
}
int main(){
LinkList linklist = NULL;
createLinkList(linklist);
display(linklist);
return 0;
}
标签:LinkList,head,NULL,int,next,链表,数据结构,data,逆置 From: https://blog.51cto.com/u_12606187/5959761