赌一手今年 CSP 必考高精。
加法:
#include <bits/stdc++.h>
using namespace std;
string a, b;
vector<int> add(vector<int> A, vector<int> B) {
if (A.size() < B.size()) return add(B, A);
vector<int> C;
int t = 0;
for (int i = 0; i < A.size(); i++) {
t += A[i];
if (i < B.size()) t += B[i];
C.push_back(t % 10);
t /= 10;
}
if (t) C.push_back(t);
return C;
}
void output(vector<int> C) {
for (int i = C.size() - 1; i >= 0; i--) cout << C[i];
}
int main() {
vector<int> A, B;
cin >> a >> b;
for (int i = a.size() - 1; i >= 0; i--) A.push_back(a[i] - '0');
for (int i = b.size() - 1; i >= 0; i--) B.push_back(b[i] - '0');
vector<int> C = add(A, B);
output(C);
}
减法、
#include <bits/stdc++.h>
using namespace std;
string a, b;
vector<int> add(vector<int> A, vector<int> B) {
if (A.size() < B.size()) return add(B, A);
vector<int> C;
int t = 0;
for (int i = 0; i < A.size(); i++) {
t = A[i] - t;
if (i < B.size()) t -= B[i];
C.push_back((t + 10) % 10);
if (t < 0) t = 1;
else t = 0;
}
while (C.size() > 1 && C.back() == 0) C.pop_back();
return C;
}
void output(vector<int> C) {
for (int i = C.size() - 1; i >= 0; i--) cout << C[i];
}
int main() {
vector<int> A, B;
cin >> a >> b;
for (int i = a.size() - 1; i >= 0; i--) A.push_back(a[i] - '0');
for (int i = b.size() - 1; i >= 0; i--) B.push_back(b[i] - '0');
vector<int> C = add(A, B);
output(C);
}
乘法(高精*低精)
#include <bits/stdc++.h>
using namespace std;
string a;
int b;
vector<int> mul(vector<int> A, int b) {
vector<int> C;
int t = 0;
for (int i = 0; i < A.size(); i++) {
t += A[i] * b;
C.push_back(t % 10);
t /= 10;
}
while (t) {
C.push_back(t % 10);
t /= 10;
}
while (C.size() > 1 && C.back() == 0) C.pop_back();
return C;
}
void output(vector<int> C) {
for (int i = C.size() - 1; i >= 0; i--) cout << C[i];
}
int main() {
vector<int> A;
cin >> a >> b;
for (int i = a.size() - 1; i >= 0; i--) A.push_back(a[i] - '0');
output(mul(A, b));
}
除法(高精/低精)
#include <bits/stdc++.h>
using namespace std;
string a;
int b, r;
vector<int> div(vector<int> A, int b) {
vector<int> C;
for (int i = 0; i < A.size(); i++) {
r = r * 10 + A[i];
C.push_back(r / b);
r %= b;
}
reverse(C.begin(), C.end());
while (C.size() > 1 && C.back() == 0) C.pop_back();
return C;
}
void output(vector<int> C) {
for (int i = C.size() - 1; i >= 0; i--) cout << C[i];
puts("");
cout << r << endl;
}
int main() {
vector<int> A;
cin >> a >> b;
for (int i = 0; i < a.size(); i++) A.push_back(a[i] - '0');
output(div(A, b));
}
标签:10,高精度,int,back,vector,push,模板,size
From: https://www.cnblogs.com/stOtue/p/16633823.html