This is a demo task.
Write a function:
class Solution { public int solution(int[] A); }
that, given an array A of N integers, returns the smallest positive integer (greater than 0) that does not occur in A.
For example, given A = [1, 3, 6, 4, 1, 2], the function should return 5.
Given A = [1, 2, 3], the function should return 4.
Given A = [−1, −3], the function should return 1.
Write an efficient algorithm for the following assumptions:
- N is an integer within the range [1..100,000];
- each element of array A is an integer within the range [−1,000,000..1,000,000].
查看代码
public int solution(int[] A) {
Set<Integer> nums = new HashSet<>();
for(int a : A) {
if (a > 0) {
nums.add(a);
}
}
for (int i = 1; i <= A.length + 1; i++) {
if (!nums.contains(i)) {
return i;
}
}
return 1;
}