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LeetCode: 225. Implement Stack using Queues

时间:2022-12-05 18:05:34浏览次数:43  
标签:Queues top pop LeetCode push Stack stk stack empty


LeetCode: 225. Implement Stack using Queues

题目描述

Implement the following operations of a stack using queues.

  • ​push(x)​​ – Push element x onto stack.
  • ​pop()​​ – Removes the element on top of the stack.
  • ​top()​​ – Get the top element.
  • ​empty()​​​ – Return whether the stack is empty.
    Example:
MyStack stack = new MyStack();

stack.push(1);
stack.push(2);
stack.top(); // returns 2
stack.pop(); // returns 2
stack.empty(); // returns false

Notes:

  • You must use only standard operations of a queue – which means only push to back, peek/pop from front, size, and is empty operations are valid.
  • Depending on your language, queue may not be supported natively. You may simulate a queue by using a list or deque (double-ended queue), as long as you use only standard operations of a queue.
  • You may assume that all operations are valid (for example, no pop or top operations will be called on an empty stack).

解题思路

用两个队列,将 ​​push​​ 的数据反向写入队列中。

AC 代码

class MyStack {
public:
/** Initialize your data structure here. */
MyStack() {

}

/** Push element x onto stack. */
void push(int x) {
queue<int> que;

while(!m_stk.empty())
{
que.push(m_stk.front());
m_stk.pop();
}

m_stk.push(x);

while(!que.empty())
{
m_stk.push(que.front());
que.pop();
}
}

/** Removes the element on top of the stack and returns that element. */
int pop() {
int t = top();
m_stk.pop();

return t;
}

/** Get the top element. */
int top() {
return m_stk.front();
}

/** Returns whether the stack is empty. */
bool empty() {
return m_stk.empty();
}

private:
queue<int> m_stk;
};

/**
* Your MyStack object will be instantiated and called as such:
* MyStack obj = new MyStack();
* obj.push(x);
* int param_2 = obj.pop();
* int param_3 = obj.top();
* bool param_4 = obj.empty();
*/


标签:Queues,top,pop,LeetCode,push,Stack,stk,stack,empty
From: https://blog.51cto.com/u_15903085/5913202

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