An array A consisting of N different integers is given. The array contains integers in the range [1..(N + 1)], which means that exactly one element is missing.
Your goal is to find that missing element.
Write a function:
class Solution { public int solution(int[] A); }
that, given an array A, returns the value of the missing element.
For example, given array A such that:
A[0] = 2 A[1] = 3 A[2] = 1 A[3] = 5
the function should return 4, as it is the missing element.
Write an efficient algorithm for the following assumptions:
- N is an integer within the range [0..100,000];
- the elements of A are all distinct;
- each element of array A is an integer within the range [1..(N + 1)].
class Solution {
public int solution(int[] A) {
// write your code in Java SE 8
if(A.length == 0) {
return 1;
}
BitSet bs = new BitSet();
for (int i = 0; i < A.length; i++) {
bs.set(A[i]);
}
int ret = -1;
for (int i = 1; i <= A.length + 1; i++) {
if (!bs.get(i)) {
ret = i;
break;
}
}
return ret;
}
}
标签:given,..,missing,PermMissingElem,element,int,Complexity,Time,array From: https://www.cnblogs.com/KresnikShi/p/16941041.html