Fizz Buzz

一、题目描述

给定一个整数你，找到从1到n各个整数的FizzBizz表示，并用字符串数组answe（下表1开始）返回结果，其中：
answer[i] == "FizzBuzz" 同时是3和5的倍数
answer[i] == "Fizz" 如果i是3的倍数
answer[i] == "Buzz" 如果i是5的倍数
answer[i] == i 如果上述条件全不满足
示例1

输入：n = 3
输出：["1","2","Fizz"]

示例2

输入：n = 5
输出：["1","2","Fizz","4","Buzz"]

示例3

输入：n = 15
输出：["1","2","Fizz","4","Buzz","Fizz","7","8","Fizz","Buzz","11","Fizz","13","14","FizzBuzz"]

二、解题思路
遍历一个数组，检查索引，判断条件，是否为3或者5的倍数，将值存在数组中并返回即可。
三、解题方法
使用数组进行条件筛选，由于数组开始下表为0，所以需要加一。
代码实现

class Solution {
    public List<String> fizzBuzz(int n) {

        String[] list = new String[n+1];

        for(int i=1; i<=n; i++){
            if( i%3==0 && i%5!=0){
                list[i] = "Fizz";
            }else if(i%5 == 0 && i%3!=0){
                list[i] = "Buzz";
            }else if(i%5 == 0 && i%3==0){
                list[i] = "FizzBuzz";
            }else{
                list[i] = i+"";
            }
            
        }

        return Arrays.asList(Arrays.copyOfRange(list,1,n+1));
    }
}