1002. A+B for Polynomials (25)

1002. A+B for Polynomials (25)

时间限制

400 ms

内存限制

65536 kB

代码长度限制

16000 B

判题程序

Standard

作者

CHEN, Yue

This time, you are supposed to find A+B where A and B are two polynomials.

Input

Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K N1 a_N1 N2 a_N2 ... NK a_NK, where K is the number of nonzero terms in the polynomial, Ni and a_Ni (i=1, 2, ..., K) are the exponents and coefficients, respectively. It is given that 1 <= K <= 10，0 <= NK < ... < N2 < N1 <=1000.

Output

For each test case you should output the sum of A and B in one line, with the same format as the input. Notice that there must be NO extra space at the end of each line. Please be accurate to 1 decimal place.

Sample Input

2 1 2.4 0 3.2
2 2 1.5 1 0.5

Sample Output

3 2 1.5 1 2.9 0 3.2

比较的时候要有fabs()    double的绝对值  #include<math.h>

评测结果

测试点

#include<iostream>
#include<iomanip>
#include<math.h>
using namespace std;
#define esp 0.04
int main()
{
 double index[1001]={0};
 int n,a,count; 
 double e;
 cin>>n; 
 while(n--)
 {
  cin>>a>>e; 
  index[a]=e;
 } 
 cin>>n;
 while(n--)
 {
  cin>>a>>e; 
   index[a]+=e; 
 }
 n=1001;
 count=0;
 while(n--)
 {
  if(fabs(index[n])>esp)count++;
 }
 cout<<count;
 n=1001;
 while(n--)
 {
  if(fabs(index[n])>esp){
            cout<<" "<<n<<" ";
   cout<<setiosflags(ios::fixed)<<setprecision(1)<<index[n];}
 }
 cout<<endl;
 return 0;
}