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Codeforces864B-Polycarp and Letters

时间:2022-11-22 19:02:49浏览次数:69  
标签:ch Letters string Polycarp positions uppercase letters ans Codeforces864B



Polycarp and Letters

Polycarp loves lowercase letters and dislikes uppercase ones. Once he got a string sconsisting only of lowercase and uppercase Latin letters.

Let A be a set of positions in the string. Let's call it pretty

  • letters on positions from A
  • there are no uppercase letters in the string which are situated between positions from A (i.e. there is no such j that s[j] is an uppercase letter, anda1 < j < a2 for some a1 and a2 from A).

Write a program that will determine the maximum number of elements in a pretty

Input

The first line contains a single integer n (1 ≤ n ≤ 200) — length of string s.

The second line contains a string s

Output

Print maximum number of elements in pretty set of positions for string s.

Example

Input


11 aaaaBaabAbA


Output


2


Input


12 zACaAbbaazzC


Output


3


Input


3 ABC


Output


0

Note

In the first example the desired positions might be 6 and 8 or 7 and 8. Positions 6and 7 contain letters 'a', position 8 contains letter 'b'. The pair of positions 1and 8 is not suitable because there is an uppercase letter 'B' between these position.

In the second example desired positions can be 7, 8 and 11. There are other ways to choose pretty

In the third example the given string s does not contain any lowercase letters, so the answer is 0.


题意:给出一个字符串,由一个个大写字母分隔成多个区域。求各个区域中最多的不同的字母个数的数量。依然模拟求解。

Code:

var
l,i,ans,k:longint;ch:char;
a:array['a'..'z'] of longint;
begin
readln(l);
for i:=1 to l do
begin
read(ch);
if (ch>='a')and(ch<='z') then
begin
inc(a[ch]);
if a[ch]=1 then inc(k);
end else
begin
if k>ans then ans:=k;
k:=0;
fillchar(a,sizeof(a),0);
end;
end;
if k>ans then ans:=k;
writeln(ans);
end.

标签:ch,Letters,string,Polycarp,positions,uppercase,letters,ans,Codeforces864B
From: https://blog.51cto.com/u_15888102/5878359

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