平方数之和
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algorithms Medium (39.41%) 403 -
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给定一个非负整数 c ，你要判断是否存在两个整数 a 和 b，使得 a2 + b2 = c 。
示例 1：
输入：c = 5
输出：true
解释：1 * 1 + 2 * 2 = 5
示例 2：
输入：c = 3
输出：false
提示：
0 <= c <= 231 - 1
Discussion | Solution
class Solution {
public:
bool judgeSquareSum(int c) {
int max = sqrt(c);
int l = 0;
while(l <= max)
{
long value = (long)l*l + (long)max*max;
if(value == c)
return true;
else if(value < c)
l++;
else
max--;
}
return false;
}
};