检查脚本
修复脚本
#!/bin/bash
Count_passmin=`cat /etc/profile | grep -n ^PASS_MIN_DAYS | awk -F[:] '{print $1}'`
if [ "$Count_passmin" ];then
Num_passmin=1
for a in $Count_passmin
do
echo $Num_passmin
if [ $Num_passmin == 1 ];then
sed -i $a'c PASS_MIN_DAYS 2' /etc/profile
else
sed -i $a'c #PASS_MIN_DAYS重复配置已替换' /etc/profile
fi
Num_passmin=$Num_passmin+1
done
else
echo "PASS_MIN_DAYS 2" >> /etc/profile
fi标签：脚本,profile,Shell,MIN,DAYS,案例,Num,passmin,PASS From： https://www.cnblogs.com/Magiclala/p/17079261.html