SQL RIGHT JOIN 返回右表中的所有行,即使左表中没有匹配项也是如此,这意味着右连接返回右表中的所有值,再加上左表中的匹配值,如果没有匹配则返回NULL。
RIGHT JOIN - 语法
RIGHT JOIN 的基本语法如下。
SELECT table1.column1, table2.column2... FROM table1 RIGHT JOIN table2 ON table1.common_field=table2.common_field;
RIGHT JOIN - 示例
考虑以下两个表,
表1 -客户表(CUSTOMERS)如下。
+----+----------+-----+-----------+----------+ | ID | NAME | AGE | ADDRESS | SALARY | +----+----------+-----+-----------+----------+ | 1 | Ramesh | 32 | Ahmedabad | 2000.00 | | 2 | Khilan | 25 | Delhi | 1500.00 | | 3 | kaushik | 23 | Kota | 2000.00 | | 4 | Chaitali | 25 | Mumbai | 6500.00 | | 5 | Hardik | 27 | Bhopal | 8500.00 | | 6 | Komal | 22 | MP | 4500.00 | | 7 | Learnfk | 24 | Indore | 10000.00 | +----+----------+-----+-----------+----------+
表2 -订单表(ORDERS)如下。
+-----+---------------------+-------------+--------+ |OID | DATE | CUSTOMER_ID | AMOUNT | +-----+---------------------+-------------+--------+ | 102 | 2019-10-08 00:00:00 | 3 | 3000 | | 100 | 2019-10-08 00:00:00 | 3 | 1500 | | 101 | 2019-11-20 00:00:00 | 2 | 1560 | | 103 | 2018-05-20 00:00:00 | 4 | 2060 | +-----+---------------------+-------------+--------+
现在,让无涯教程使用RIGHT JOIN联接这两个表,如下所示。
SQL> SELECT ID, NAME, AMOUNT, DATE FROM CUSTOMERS RIGHT JOIN ORDERS ON CUSTOMERS.ID=ORDERS.CUSTOMER_ID;
这将产生以下输出-
+------+----------+--------+---------------------+ | ID | NAME | AMOUNT | DATE | +------+----------+--------+---------------------+ | 3 | kaushik | 3000 | 2019-10-08 00:00:00 | | 3 | kaushik | 1500 | 2019-10-08 00:00:00 | | 2 | Khilan | 1560 | 2019-11-20 00:00:00 | | 4 | Chaitali | 2060 | 2018-05-20 00:00:00 | +------+----------+--------+---------------------+
参考链接
https://www.learnfk.com/sql/sql-right-joins.html
标签:00,RIGHT,JOIN,无涯,2019,20,ID From: https://blog.51cto.com/u_14033984/9279275