hive SQL案例

标签：rn1 hive 案例 user SQL date dt2 login id

• 上个月用户连续n天登录天数

用户登录记录表user_login，包括用户id（user_id）、日期（login_date）

user_id	login_date
12333256	2021-01-03
84272916	2021-01-03
94038271	2021-01-02
201934012	2021-01-03

过滤出当月数据：where login_date > ''
转换成date：to_date函数，参数默认按照"yyyy-MM-dd"的格式 去重：一天可能有多次登录记录（distinct、group by、row_number）； 开窗排序，生成rn1：按user_id分区，login_date排序 login_date与rn1作差得到新日期dt2：date_sub(login_date, rn1) 统计天数：按user_id、dt2分组，再使用count(1)统计连续登录天数 开窗排序，生成rn2：按user_id分区，count(1)排序

with t1 as (
    select
        user_id, 
        to_date(login_date) as dt1,
        row_number() over(partition by user_id order by to_date(login_date)) as rn1
    from db.user_login
    where login_date > '2023-07-31'
    group by user_id, to_date(login_date)
),
t2 as (
    select
        user_id,
        date_sub(dt1, rn1) as dt2
    from t1
),
t3 as (
    select
        user_id,
        dt2,
        count(1) as continuous_day,
        row_number() over(partition by user_id order by count(1) desc) rn2
    from t2
    group by user_id, dt2
)
select
    user_id,
    dt2
from t3
where rn2 = 1;

View Code

 

 

标签：rn1,hive,案例,user,SQL,date,dt2,login,id
From： https://www.cnblogs.com/lcmichelle/p/17659916.html