mysql根据当前数据查上一条，下一条数据

1、如果是id自增，按id比较大小取上一条，下一条就行，简单

2、不是id自增，按时间排序的列表数据，用以下sql解决

=====================根据时间排序，查上一条

t_pubservice_content 要查询的表，push_time 为排序的时间字段

select t1.* from(
 select @num:=@num-2 as rownum, tpc.*
 from t_pubservice_content tpc,(select @num:=0) as r
 WHERE tpc.cloumn_id = '1664827884371091458'
 order by push_time desc
) t1,(
    select curNum from(
        select @num2:=@num2-2 as curNum, tpc.*
        from t_pubservice_content tpc,(select @num2:=0) r2
        WHERE tpc.cloumn_id = '1664827884371091458'
        order by push_time desc
    ) t where id = '1666995762037964828'
)t2 where rownum > curNum
order by rownum
limit 1

=====================根据时间排序，查上下条

select t1.* from(
 select @num:=@num+1 as rownum, tpc.*
 from t_pubservice_content tpc,(select @num:=0) as r
 WHERE tpc.cloumn_id = '1664827884371091458'
 order by push_time desc
) t1,(
    select curNum from(
        select @num2:=@num2+1 as curNum, tpc.*
        from t_pubservice_content tpc,(select @num2:=0) r2
        WHERE tpc.cloumn_id = '1664827884371091458'
        order by push_time desc
    ) t where id = '1666995661924122631'
)t2 where rownum > curNum
order by rownum
limit 1

。