c# winform 读取oracle中blob字段的图片并且显示到pictureBox里，保存进库

private void button2_Click(object sender, EventArgs e)
{
	OracleConnection conn = dbc.getConnection();//获得conn连接
	try
	{
		conn.Open();
		OracleCommand cmd = conn.CreateCommand();
		cmd.CommandText = "SELECT zp FROM kk.kkbj WHERE xh = 2345 ";//查询获得图片流

		OracleDataReader reader = cmd.ExecuteReader();//创建一个OracleDateReader对象 
		reader.Read();

		MemoryStream ms = new MemoryStream((byte[])reader["zp"]);

		Image image = Image.FromStream(ms, true);

		reader.Close();
		conn.Close();

		pictureBox1.Image = image;
	}
	catch (Exception ee)
	{
		MessageBox.Show(ee.Message.ToString());
	}

}

[color=red]----------下边是上传和存入数据库有asp.net和winform(转)----------------------------------[/color]

本文总结如何在.Net Winform和.Net webform(asp.net)中将图片存入sqlserver中并读取显示的方法

1，使用asp.net将图片上传并存入SqlServer中，然后从SqlServer中读取并显示出来

一，上传并存入SqlServer

数据库结构

create table test 

{ 

 id identity(1,1), 

 FImage image 

} 


 相关的存储过程 

Create proc UpdateImage 

( 

 @UpdateImage Image 

) 

As 

Insert Into test(FImage) values(@UpdateImage) 

GO

在UpPhoto.aspx文件中添加如下:

<input id="UpPhoto" name="UpPhoto" runat="server" type="file">
<asp:Button id="btnAdd" name="btnAdd" runat="server" Text="上传"></asp:Button>

然后在后置代码文件UpPhoto.aspx.cs添加btnAdd按钮的单击事件处理代码:

private void btnAdd_Click(object sender, System.EventArgs e)
{
        //获得图象并把图象转换为byte[]
        HttpPostedFile upPhoto=UpPhoto.PostedFile;
        int upPhotoLength=upPhoto.ContentLength;
        byte[] PhotoArray=new Byte[upPhotoLength];
        Stream PhotoStream=upPhoto.InputStream;
        PhotoStream.Read(PhotoArray,0,upPhotoLength);

        //连接数据库
        SqlConnection conn=new SqlConnection();
        conn.ConnectionString="Data Source=localhost;Database=test;User Id=sa;Pwd=sa";

        SqlCommand cmd=new SqlCommand("UpdateImage",conn);
        cmd.CommandType=CommandType.StoredProcedure;

        cmd.Parameters.Add("@UpdateImage",SqlDbType.Image);
        cmd.Parameters["@UpdateImage"].Value=PhotoArray;

        //如果你希望不使用存储过程来添加图片把上面四句代码改为：
        //string strSql="Insert into test(FImage) values(@FImage)";
        //SqlCommand cmd=new SqlCommand(strSql,conn);
        //cmd.Parameters.Add("@FImage",SqlDbType.Image);
        //cmd.Parameters["@FImage"].Value=PhotoArray;

conn.Open();
cmd.ExecuteNonQuery();
conn.Close();
}

二，从SqlServer中读取并显示出来

在需要显示图片的地方添加如下代码:

<asp:image id="imgPhoto" runat="server" ImageUrl="ShowPhoto.aspx"></asp:image>

ShowPhoto.aspx主体代码：

private void Page_Load(object sender, System.EventArgs e)
{
     if(!Page.IsPostBack)
     {
                SqlConnection conn=new SqlConnection()
                conn.ConnectionString="Data Source=localhost;Database=test;User Id=sa;Pwd=sa";

                string strSql="select * from test where id=2";//这里假设获取id为2的图片
                SqlCommand cmd=new SqlCommand()
                reader.Read();
                Response.ContentType="application/octet-stream";
                Response.BinaryWrite((Byte[])reader["FImage"]);
                Response.End();
                reader.Close();
     }
}

3，在winform中将图片存入sqlserver，并从sqlserver中读取并显示在picturebox中

1,存入sqlserver

数据库结构和使用的存储过过程，同上面的一样

1.1,在窗体中加一个OpenFileDialog控件，命名为ofdSelectPic

1.2,在窗体上添加一个打开文件按钮，添加如下单击事件代码：

Stream ms;
byte[] picbyte;
//ofdSelectPic.ShowDialog();
if (ofdSelectPic.ShowDialog()==DialogResult.OK)
{
   if ((ms=ofdSelectPic.OpenFile())!=null)
   {
    //MessageBox.Show("ok");
    picbyte=new byte[ms.Length];
    ms.Position=0;
    ms.Read(picbyte,0,Convert.ToInt32(ms.Length));
    //MessageBox.Show("读取完毕!");

    //连接数据库
    SqlConnection conn=new SqlConnection();
    conn.ConnectionString="Data Source=localhost;Database=test;User Id=sa;Pwd=sa";

    SqlCommand cmd=new SqlCommand("UpdateImage",conn);
    cmd.CommandType=CommandType.StoredProcedure;

    cmd.Parameters.Add("@UpdateImage",SqlDbType.Image);
    cmd.Parameters["@UpdateImage"].Value=picbyte;

    conn.Open();
    cmd.ExecuteNonQuery();
    conn.Close();

    ms.Close();
    }
   }

2,读取并显示在picturebox中

2.1 添加一个picturebox,名为ptbShow

2.2 添加一个按钮，添加如下响应事件：

SqlConnection conn=new SqlConnection();
conn.ConnectionString="Data Source=localhost;Database=test;User Id=sa;Pwd=sa";

string strSql="select FImage from test where id=1";

SqlCommand cmd=new SqlCommand(strSql,conn);

conn.Open();
SqlDataReader reader=cmd.ExecuteReader();
        reader.Read();

MemoryStream ms=new MemoryStream((byte[])reader["FImage"]);

Image image=Image.FromStream(ms,true);

        reader.Close();
        conn.Close();

ptbShow.Image=image;

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