给定一个开始日期和结束日期,写个sql把中间的每天都查出来(包括开始和结束日期)。
给定开始时间是2023-03-12,结束时间是2023-03-22,sql如下:
SELECT DATE_ADD('2023-03-12', INTERVAL seq DAY) AS `day` FROM ( SELECT 0 seq UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9 UNION ALL SELECT 10 ) t WHERE DATE_ADD('2023-03-12', INTERVAL seq DAY) <= '2023-03-22'
查询结果
day 2023-03-12 2023-03-13 2023-03-14 2023-03-15 2023-03-16 2023-03-17 2023-03-18 2023-03-19 2023-03-20 2023-03-21 2023-03-22
如果要动态处理,可以使用mybatis的foreach标签处理该sql
参数dateStart、dateEnd、numList分别代表开始时间、结束时间、差值数集合
SELECT DATE_ADD(DATE_FORMAT(#{dateStart},'%Y-%m-%d'), INTERVAL seq DAY) AS `day` FROM ( SELECT 0 seq UNION ALL <foreach collection="numList" item="numItem" separator=" UNION ALL " open=" " close=" "> SELECT #{numItem} </foreach> ) WHERE DATE_ADD(DATE_FORMAT(#{dateStart},'%Y-%m-%d'), INTERVAL seq DAY) <= DATE_FORMAT(#{dateEnd},'%Y-%m-%d')
标签:03,seq,UNION,起止日期,日期,sql,2023,DATE,SELECT From: https://www.cnblogs.com/shamo89/p/17248212.html