【SQL题目】获取每个部门中当前员工薪水最高的相关信息

标签：01 题目 no 薪水 9999 dept emp SQL date

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描述

有一个员工表dept_emp简况如下:

emp_no	dept_no	from_date	to_date
10001	d001	1986-06-26	9999-01-01
10002	d001	1996-08-03	9999-01-01
10003	d002	1996-08-03	9999-01-01

  有一个薪水表salaries简况如下:

emp_no	salary	from_date	to_date
10001	88958	2002-06-22	9999-01-01
10002	72527	2001-08-02	9999-01-01
10003	92527	2001-08-02	9999-01-01

  获取每个部门中当前员工薪水最高的相关信息，给出dept_no, emp_no以及其对应的salary，按照部门编号dept_no升序排列，以上例子输出如下:

dept_no	emp_no	maxSalary
d001	10001	88958
d002	10003	92527

示例1

输入：

drop table if exists  `dept_emp` ; 
drop table if exists  `salaries` ; 
CREATE TABLE `dept_emp` (
`emp_no` int(11) NOT NULL,
`dept_no` char(4) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`dept_no`));
CREATE TABLE `salaries` (
`emp_no` int(11) NOT NULL,
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`from_date`));
INSERT INTO dept_emp VALUES(10001,'d001','1986-06-26','9999-01-01');
INSERT INTO dept_emp VALUES(10002,'d001','1996-08-03','9999-01-01');
INSERT INTO dept_emp VALUES(10003,'d002','1996-08-03','9999-01-01');

INSERT INTO salaries VALUES(10001,88958,'2002-06-22','9999-01-01');
INSERT INTO salaries VALUES(10002,72527,'2001-08-02','9999-01-01');
INSERT INTO salaries VALUES(10003,92527,'2001-08-02','9999-01-01');

输出：

d001|10001|88958
d002|10003|92527

题解：

select a.dept_no,a.emp_no,a.salary
from
(select d.dept_no dept_no,d.emp_no emp_no,s.salary salary
from dept_emp d join salaries s
on d.emp_no = s.emp_no) a
right join
(select d.dept_no dept_no,max(s.salary) salary
from dept_emp d join salaries s
on d.emp_no = s.emp_no
group by d.dept_no order by d.dept_no) b
on a.dept_no = b.dept_no and a.salary = b.salary;

 

标签：01,题目,no,薪水,9999,dept,emp,SQL,date
From： https://www.cnblogs.com/camping/p/17112776.html