实验任务1
1，自定义了两个类分别是window类和button类
使用了标准库中的iostream vector string
2,不适合
3定义了一个字符串长度为40
实验任务2
1 #include <iostream>
2 #include <vector>
3
4 using namespace std;
5
6 void output1(const vector<int> &v) {
7 for(auto &i: v)
8 cout << i << ", ";
9 cout << "\b\b \n";
10 }
11
12 void output2(const vector<vector<int>> v) {
13 for(auto &i: v) {
14 for(auto &j: i)
15 cout << j << ", ";
16 cout << "\b\b \n";
17 }
18 }
19
20 void test1() {
21 vector<int> v1(5, 42);
22 const vector<int> v2(v1);
23
24 v1.at(0) = -999;
25 cout << "v1: "; output1(v1);
26 cout << "v2: "; output1(v2);
27 cout << "v1.at(0) = " << v1.at(0) << endl;
28 cout << "v2.at(0) = " << v2.at(0) << endl;
29 }
30
31 void test2() {
32 vector<vector<int>> v1{{1, 2, 3}, {4, 5, 6, 7}};
33 const vector<vector<int>> v2(v1);
34
35 v1.at(0).push_back(-999);
36 cout << "v1: \n"; output2(v1);
37 cout << "v2: \n"; output2(v2);
38
39 vector<int> t1 = v1.at(0);
40 cout << t1.at(t1.size()-1) << endl;
41
42 const vector<int> t2 = v2.at(0);
43 cout << t2.at(t2.size()-1) << endl;
44 }
45
46 int main() {
47 cout << "测试1:\n";
48 test1();
49
50 cout << "\n测试2:\n";
51 test2();
52 }
View Code
问题1
1 vector<int> v1(5, 42); 2 const vector<int> v2(v1); 3 4 v1.at(0) = -999;
1：构造并初始化5个42
2：拷贝构造v1
3：at访问
问题2
1 vector<vector<int>> v1{{1, 2, 3}, {4, 5, 6, 7}};
2 const vector<vector<int>> v2(v1);
3
4 v1.at(0).push_back(-999);
1：初始化v1为两个｛1，2，3｝和｛4，5，6，7｝
2: 拷贝构造v1
3：在尾端插入v1.at（0）
问题3
1 vector<int> t1 = v1.at(0); 2 cout << t1.at(t1.size()-1) << endl; 3 4 const vector<int> t2 = v2.at(0); 5 cout << t2.at(t2.size()-1) << endl;
1：初始化t1为v1.at(0) t1能够进行修改
2:输出
3：初始化t2为v2.at(0) t2不能进行修改
4：输出
实验任务3
1 #pragma once
2
3 #include <iostream>
4 #include <cassert>
5
6 using std::cout;
7 using std::endl;
8
9 // 动态int数组对象类
10 class vectorInt{
11 public:
12 vectorInt(int n);
13 vectorInt(int n, int value);
14 vectorInt(const vectorInt &vi);
15 ~vectorInt();
16
17 int& at(int index);
18 const int& at(int index) const;
19
20 vectorInt& assign(const vectorInt &v);
21 int get_size() const;
22
23 private:
24 int size;
25 int *ptr; // ptr指向包含size个int的数组
26 };
27
28 vectorInt::vectorInt(int n): size{n}, ptr{new int[size]} {
29 }
30
31 vectorInt::vectorInt(int n, int value): size{n}, ptr{new int[size]} {
32 for(auto i = 0; i < size; ++i)
33 ptr[i] = value;
34 }
35
36 vectorInt::vectorInt(const vectorInt &vi): size{vi.size}, ptr{new int[size]} {
37 for(auto i = 0; i < size; ++i)
38 ptr[i] = vi.ptr[i];
39 }
40
41 vectorInt::~vectorInt() {
42 delete [] ptr;
43 }
44
45 const int& vectorInt::at(int index) const {
46 assert(index >= 0 && index < size);
47
48 return ptr[index];
49 }
50
51 int& vectorInt::at(int index) {
52 assert(index >= 0 && index < size);
53
54 return ptr[index];
55 }
56
57 vectorInt& vectorInt::assign(const vectorInt &v) {
58 delete[] ptr; // 释放对象中ptr原来指向的资源
59
60 size = v.size;
61 ptr = new int[size];
62
63 for(int i = 0; i < size; ++i)
64 ptr[i] = v.ptr[i];
65
66 return *this;
67 }
68
69 int vectorInt::get_size() const {
70 return size;
71 }
1 #include "vectorInt.hpp"
2 #include <iostream>
3
4 using std::cin;
5 using std::cout;
6
7 void output(const vectorInt &vi) {
8 for(auto i = 0; i < vi.get_size(); ++i)
9 cout << vi.at(i) << ", ";
10 cout << "\b\b \n";
11 }
12
13
14 void test1() {
15 int n;
16 cout << "Enter n: ";
17 cin >> n;
18
19 vectorInt x1(n);
20 for(auto i = 0; i < n; ++i)
21 x1.at(i) = i*i;
22 cout << "x1: "; output(x1);
23
24 vectorInt x2(n, 42);
25 vectorInt x3(x2);
26 x2.at(0) = -999;
27 cout << "x2: "; output(x2);
28 cout << "x3: "; output(x3);
29 }
30
31 void test2() {
32 const vectorInt x(5, 42);
33 vectorInt y(10, 0);
34
35 cout << "y: "; output(y);
36 y.assign(x);
37 cout << "y: "; output(y);
38
39 cout << "x.at(0) = " << x.at(0) << endl;
40 cout << "y.at(0) = " << y.at(0) << endl;
41 }
42
43 int main() {
44 cout << "测试1: \n";
45 test1();
46
47 cout << "\n测试2: \n";
48 test2();
49 }
问题一
深复制
问题二
不可以运行，修改完之后数据有安全风险
实验任务4
1 #pragma once
2
3 #include <cassert>
4 #include <iostream>
5
6 using std::cout;
7 using std::endl;
8
9 // 类Matrix的声明
10 class Matrix {
11 public:
12 Matrix(int n, int m); // 构造函数，构造一个n*m的矩阵, 初始值为value
13 Matrix(int n); // 构造函数，构造一个n*n的矩阵, 初始值为value
14 Matrix(const Matrix &x); // 复制构造函数， 使用已有的矩阵X构造
15 ~Matrix();
16
17 void set(const double *pvalue); // 用pvalue指向的连续内存块数据按行为矩阵赋值
18 void clear(); // 把矩阵对象的值置0
19
20 const double &at(int i, int j) const; // 返回矩阵对象索引(i,j)的元素const引用
21 double &at(int i, int j); // 返回矩阵对象索引(i,j)的元素引用
22
23 int get_lines() const; // 返回矩阵对象行数
24 int get_cols() const; // 返回矩阵对象列数
25
26 void display() const; // 按行显示矩阵对象元素值
27
28 private:
29 int lines; // 矩阵对象内元素行数
30 int cols; // 矩阵对象内元素列数
31 double *ptr;
32 };
33
34 // 类Matrix的实现：待补足
35 Matrix::Matrix(int n, int m) : lines(n), cols(m) {
36 ptr = new double[n * m];
37 clear();
38 }
39
40 Matrix::Matrix(int n) : Matrix(n, n) {}
41
42 Matrix::Matrix(const Matrix &x) : lines(x.lines), cols(x.cols) {
43 ptr = new double[lines * cols];
44 for (int i = 0; i < lines * cols; i++)
45 ptr[i] = x.ptr[i];
46 }
47
48 Matrix::~Matrix() {
49 delete[] ptr;
50 }
51
52 void Matrix::set(const double *pvalue) {
53 for (int i = 0; i < lines * cols; i++)
54 ptr[i] = pvalue[i];
55 }
56
57 void Matrix::clear() {
58 for (int i = 0; i < lines * cols; i++)
59 ptr[i] = 0;
60 }
61
62 const double &Matrix::at(int i, int j) const {
63 assert(i >= 0 && i < lines && j >= 0 && j < cols);
64 return ptr[i * cols + j];
65 }
66
67 double &Matrix::at(int i, int j) {
68 assert(i >= 0 && i < lines && j >= 0 && j < cols);
69 return ptr[i * cols + j];
70 }
71
72 int Matrix::get_lines() const {
73 return lines;
74 }
75
76 int Matrix::get_cols() const {
77 return cols;
78 }
79
80 void Matrix::display() const {
81 for (int i = 0; i < lines; i++) {
82 for (int j = 0; j < cols; j++) {
83 cout << ptr[i * cols + j] << " ";
84 }
85 cout << endl;
86 }
87 }
88 // task4.cpp
89
90 #include "matrix.hpp"
91 #include <cassert>
92 #include <iostream>
93 #include <numeric>
94
95 using std::cin;
96 using std::cout;
97 using std::endl;
98
99 const int N = 1000;
100
101 // 输出矩阵对象索引为index所在行的所有元素
102 void output(const Matrix &m, int index) {
103 assert(index >= 0 && index < m.get_lines());
104
105 for (auto j = 0; j < m.get_cols(); ++j)
106 cout << m.at(index, j) << ", ";
107 cout << "\b\b \n";
108 }
109
110 void test1() {
111 double x[1000];
112
113 std::iota(x, x + N, 1); // 用1到N初始化数组x
114
115 int n, m;
116 cout << "Enter n and m: ";
117 cin >> n >> m;
118
119 Matrix m1(n, m); // 创建矩阵对象m1, 大小n×m
120 m1.set(x); // 用一维数组x的值按行为矩阵m1赋值
121
122 Matrix m2(m, n); // 创建矩阵对象m1, 大小m×n
123 m2.set(x); // 用一维数组x的值按行为矩阵m1赋值
124
125 Matrix m3(2); // 创建一个2×2矩阵对象
126 m3.set(x); // 用一维数组x的值按行为矩阵m4赋值
127
128 cout << "矩阵对象m1: \n";
129 m1.display();
130 cout << endl;
131 cout << "矩阵对象m2: \n";
132 m2.display();
133 cout << endl;
134 cout << "矩阵对象m3: \n";
135 m3.display();
136 cout << endl;
137 }
138
139 void test2() {
140 Matrix m1(2, 3);
141 m1.clear();
142
143 const Matrix m2(m1);
144 m1.at(0, 0) = -999;
145
146 cout << "m1.at(0, 0) = " << m1.at(0, 0) << endl;
147 cout << "m2.at(0, 0) = " << m2.at(0, 0) << endl;
148 cout << "矩阵对象m1第0行: ";
149 output(m1, 0);
150 cout << "矩阵对象m2第0行: ";
151 output(m2, 0);
152 }
153
154 int main() {
155 cout << "测试1: \n";
156 test1();
157
158 cout << "测试2: \n";
159 test2();
160 }
实验任务5
1 #pragma once
2
3 #include<iostream>
4 #include<vector>
5
6 using namespace std;
7
8 class User {
9 public:
10 User(const string& name1, const string& password1="123456", const string& email1="");
11 void set_email();
12 void change_password();
13 void display() const;
14 private:
15 string name;
16 string password;
17 string email;
18 };
19 User::User(const string& name1, const string& password1, const string& email1) :name { name1 }, password { password1 }, email { email1 } {
20 }
21 void User::set_email() {
22 cout << "Enter email address: ";
23 string emaill;
24 cin >> emaill;
25 while (1) {
26 if (emaill.find('@') != string::npos) {
27 email = emaill;
28 cout << "email is set successfully..." << endl;
29 break;
30 } else {
31 cout << "illegal email.Please re-enter email: ";
32 cin >> emaill;
33 cout;
34 }
35 }
36 }
37 void User::change_password() {
38 cout << "Enter old password: ";
39 string password1;
40 cin >> password1;
41 int cnts = 1;
42 while (cnts < 3) {
43 if (password1 == password) {
44 cout << "new password: ";
45 cin >> password1;
46 password = password1;
47 cout << "new password is set successfully..." ;
48 break;
49 } else {
50 cout << "password input error. Please re-enter agagin";
51 cin >> password1;
52 cnts++;
53 }
54 }
55 if (cnts == 3) cout << "password input error.Please try after a while" << endl;;
56 }
57 void User::display()const {
58 cout << "name: " << name << endl;
59 cout << "pass: " << password << endl;
60 cout << "email: " << email << endl;
61 }
View Code
1 #include "user.hpp"
2 #include <iostream>
3 #include <vector>
4 #include <string>
5
6 using std::cin;
7 using std::cout;
8 using std::endl;
9 using std::vector;
10 using std::string;
11
12 void test() {
13 vector<User> user_lst;
14
15 User u1("Alice", "2024113", "[email protected]");
16 user_lst.push_back(u1);
17 cout << endl;
18
19 User u2("Bob");
20 u2.set_email();
21 u2.change_password();
22 user_lst.push_back(u2);
23 cout << endl;
24
25 User u3("Hellen");
26 u3.set_email();
27 u3.change_password();
28 user_lst.push_back(u3);
29 cout << endl;
30
31 cout << "There are " << user_lst.size() << " users. they are: " << endl;
32 for(auto &i: user_lst) {
33 i.display();
34 cout << endl;
35 }
36 }
37
38 int main() {
39 test();
40 }
View Code
实验任务6
1 1 #pragma once
2 2 class Date {
3 3 private:
4 4 int year;
5 5 int month;
6 6 int day;
7 7 int totalDays;
8 8 public:
9 9 Date(int year, int month, int day);
10 10 int getYear()const { return year; }
11 11 int getMonth()const { return month; }
12 12 int getDay()const { return day; }
13 13 int getMaxDay()const;
14 14 bool isLeapYear()const {
15 15 return year % 4 == 0 && year % 100 != 0 || year % 400 == 0;
16 16 }
17 17 void show() const;
18 18 int distance(const Date& date)const {
19 19 return totalDays - date.totalDays;
20 20 }
21 21 };
22 22
23 23
24 24
25 25 #include"date.h"
26 26 #include<iostream>
27 27 #include<cstdlib>
28 28 using namespace std;
29 29 namespace {
30 30 const int DAYS_BEFIRE_MONTH[] = { 0,31,59,90,120,151,181,212,243,273,304 ,334,365 };
31 31 }
32 32 Date::Date(int year, int month, int day) :year(year), month(month), day(day) {
33 33 if (day <= 0 || day > getMaxDay()) {
34 34 cout << "Invalid date: ";
35 35 show();
36 36 cout << endl;
37 37 exit(1);
38 38 }
39 39 int years = year - 1;
40 40 totalDays = years * 365 + years / 4 - years / 100 + years / 400 + DAYS_BEFIRE_MONTH[month - 1] + day;
41 41 if (isLeapYear() && month > 2) totalDays++;
42 42 }
43 43 int Date::getMaxDay()const {
44 44 if (isLeapYear() &&month == 2)
45 45 return 29;
46 46 else return DAYS_BEFIRE_MONTH[month] - DAYS_BEFIRE_MONTH[month - 1];
47 47 }
48 48 void Date::show()const {
49 49 cout << getYear() << "-" << getMonth() << "-" << getDay();
50 50 }
51 51
52 52
53 53
54 54 #pragma once
55 55 #include"date.h"
56 56 #include<string>
57 57 using namespace std;
58 58 class SavingsAccount {
59 59 private:
60 60 string id;
61 61 double balance;
62 62 double rate;
63 63 Date lastDate;
64 64 double accumulation;
65 65 static double total;
66 66 void record(const Date& date, double amount, const string& desc);
67 67 void error(const string& msg) const;
68 68 double accumulate(const Date& date)const {
69 69 return accumulation + balance * date.distance(lastDate);
70 70 }
71 71 public:
72 72 SavingsAccount(const Date& date, const string& id, double rate);
73 73 const string& getId()const { return id; }
74 74 double getBalance()const { return balance; }
75 75 double getRate()const { return rate; }
76 76 static double getTotal() { return total; }
77 77 void deposit(const Date& date, double amount, const string& desc);
78 78 void withdraw(const Date& date, double amount, const string& desc);
79 79 void settle(const Date& date);
80 80 void show() const;
81 81 };
82 82
83 83
84 84
85 85 #include"account.h"
86 86 #include<cmath>
87 87 #include<iostream>
88 88 using namespace std;
89 89 double SavingsAccount::total = 0;
90 90 SavingsAccount::SavingsAccount(const Date& date, const string& id, double rate) :
91 91 id(id), balance(0), rate(rate), lastDate(date), accumulation(0) {
92 92 date.show();
93 93 cout << "\t#" << id << "created" << endl;
94 94 }
95 95 void SavingsAccount::record(const Date& date, double amount, const string& desc) {
96 96 accumulation = accumulate(date);
97 97 lastDate = date;
98 98 amount = floor(amount * 100 + 0.5) / 100;
99 99 balance += amount;
100 100 total += amount;
101 101 date.show();
102 102 cout << "\t#" << id << "\t" << amount << "\t" << balance << "\t" << desc << endl;
103 103 }
104 104 void SavingsAccount::error(const string& msg) const {
105 105 cout << "Error(#" << id << "):" << msg << endl;
106 106 }
107 107 void SavingsAccount::deposit(const Date& date, double amount, const string& desc) {
108 108 record(date, amount, desc);
109 109 }
110 110 void SavingsAccount::withdraw(const Date& date, double amount, const string& desc) {
111 111 if (amount > getBalance())
112 112 error("not enough money");
113 113 else
114 114 record(date, -amount, desc);
115 115 }
116 116 void SavingsAccount::settle(const Date& date) {
117 117 double interest = accumulate(date) * rate / date.distance(Date(date.getYear() - 1, 1, 1));
118 118 if (interest != 0) record( date,interest,"interest" );
119 119 accumulation = 0;
120 120 }
121 121 void SavingsAccount::show()const {
122 122 cout << id << "\tBalance: " << balance;
123 123 }
124 124
125 125
126 126 #include"account.h"
127 127 #include<iostream>
128 128 using namespace std;
129 129 int main() {
130 130 Date date{ 2008,11,1 };
131 131 SavingsAccount accounts[] = {
132 132 SavingsAccount(date,"03755217",0.015),
133 133 SavingsAccount(date,"02342342",0.015)
134 134 };
135 135 const int n = sizeof(accounts) / sizeof(SavingsAccount);
136 136 accounts[0].deposit(Date(2008, 11, 5), 5000, "salary");
137 137 accounts[1].deposit(Date(2008, 11, 25), 10000, "sell stock 0323");
138 138 accounts[0].deposit(Date(2008, 12, 5), 5500, "salary");
139 139 accounts[1].withdraw(Date(2008, 12, 20), 4000, "buy a laptop");
140 140 cout << endl;
141 141 for (int i = 0; i < n; i++) {
142 142 accounts[i].settle(Date(2009, 1, 1));
143 143 accounts[i].show();
144 144 cout << endl;
145 145 }
146 146 cout << "Total: " << SavingsAccount::getTotal() << endl;
147 147 return 0;
148 148 }
149
150 task6
View Code
标签：const,cout,对象,编程,int,实验,vectorInt,ptr,Matrix From： https://www.cnblogs.com/qc050306/p/18525684