7-2 jmu-Java-04面向对象进阶-01-接口-Comparable

编写实现Comparable接口的PersonSortable类，使其按name以及age排序

1.编写PersonSortable类

属性：private name(String)、private age(int)
有参构造函数：参数为name,age
toString函数：返回格式为：name-age
实现Comparable接口：实现先对name升序排序，如果name相同则对age进行升序排序

2.main方法中

1. 首先输入n
2. 输入n行name age，并创建n个对象放入数组
3. 对数组进行排序后输出。
4. 最后一行使用System.out.println(Arrays.toString(PersonSortable.class.getInterfaces()));输出PersonSortable所实现的所有接口

输入样例:

5
zhang 15
zhang 12
wang 14
Wang 17
li 17

输出样例:

Wang-17
li-17
wang-14
zhang-12
zhang-15
//这行是标识信息

import java.util.*;
 
class PersonSortable implements Comparable{
    private String name;
    private int age;
 
    public PersonSortable() {}
 
    public PersonSortable(String name, int age) {
        this.name = name;
        this.age = age;
    }
 
    @Override
    public String toString() {
        return name+"-"+age;
    }
 
    public String getName() {
        return name;
    }
 
    public void setName(String name) {
        this.name = name;
    }
 
    public int getAge() {
        return age;
    }
 
    public void setAge(int age) {
        this.age = age;
    }
 
    @Override
    public int compareTo(Object o) {
        PersonSortable per=(PersonSortable)o;
        int x = this.name.compareTo(per.name);
        if(x!=0){
            return x;
        }else{
            if (this.age>per.age)
                return 1;
            else if(this.age<per.age)
                return -1;
            else
                return 0;
        }
    }
}
public class Main {
    public static void main(String[] args) {

        Scanner sc=new Scanner(System.in);
        int count=Integer.valueOf(sc.nextLine());
        ArrayList<PersonSortable> list=new ArrayList();

        for (int i=0;i<count;i++){
            String string[]=sc.nextLine().split(" ");
            list.add(new PersonSortable(string[0],Integer.valueOf(string[1])));
        }

        Collections.sort(list);
        for (PersonSortable p:list){
            System.out.println(p);
        }

        System.out.println(Arrays.toString(PersonSortable.class.getInterfaces()));
    }
}