1.方法一:在contextMenuStrip1打开时获取控件名称
双击contextMenuStrip1在它的opening事件中写入下面的代码:
private void contextMenuStrip1_Opening(object sender, CancelEventArgs e)
{
string whichcontrol_name= (sender as ContextMenuStrip).SourceControl.Name;
MessageBox.Show(whichcontrol_name);
}
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2.方法二:目前不是很懂
private void MenuViewDetails_Click(object sender, EventArgs e)
{
// Try to cast the sender to a ToolStripItem
ToolStripItem menuItem = sender as ToolStripItem;
if (menuItem != null)
{
// Retrieve the ContextMenuStrip that owns this ToolStripItem
ContextMenuStrip owner = menuItem.Owner as ContextMenuStrip;
if (owner != null)
{
// Get the control that is displaying this context menu
Control sourceControl = owner.SourceControl;
}
}
}
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原文链接:https://blog.csdn.net/u014683488/article/details/106189658