4. 实验任务4:
1 #include<stdio.h> 2 3 int main() 4 { 5 int i = 0; 6 FILE *fp; 7 char str[100]; 8 char ch; 9 10 fp = fopen("data4.txt","r"); 11 if(fp == NULL) 12 { 13 printf("fail to open file\n"); 14 return; 15 } 16 17 while((ch = fgetc(fp)) != EOF) 18 { 19 if(ch != '\t' && ch != '\n' && ch != ' ') 20 i++; 21 } 22 23 printf("data4.txt中共包含字符数(不计空白符):%d\n",i); 24 25 fclose(fp); 26 return 0; 27 }
5. 实验任务5:
1 #include <stdio.h> 2 #include <string.h> 3 #include <stdlib.h> 4 5 #define N 10 6 7 typedef struct { 8 long int id; 9 char name[20]; 10 float objective; // 客观题得分 11 float subjective; // 操作题得分 12 float sum; // 总分 13 char ans[10]; // 考试结果 14 } STU; 15 16 // 函数声明 17 void finput(STU st[], int n); 18 void foutput(STU st[], int n); 19 void output(STU st[], int n); 20 int process(STU st[], int n, STU st_pass[]); 21 22 int main() { 23 STU stu[N], stu_pass[N]; 24 int cnt; 25 double pass_rate; 26 27 printf("从文件读入%d个考生信息...\n", N); 28 finput(stu, N); 29 30 printf("\n对考生成绩进行统计...\n"); 31 cnt = process(stu, N, stu_pass); 32 33 printf("\n通过考试的名单:\n"); 34 output(stu_pass, cnt); // 输出到屏幕 35 foutput(stu_pass, cnt); // 输出到文件 36 37 pass_rate = 1.0 * cnt / N; 38 printf("\n本次等级考试通过率: %.2f%%\n", pass_rate*100); 39 40 return 0; 41 } 42 43 // 把通过考试的考生完整信息输出到屏幕上 44 // 准考证号,姓名,客观题得分,操作题得分,总分,结果 45 void output(STU st[], int n) { 46 int i; 47 48 printf("准考证号\t姓名\t客观题得分\t操作题得分\t总分\t\t结果\n"); 49 for (i = 0; i < n; i++) 50 printf("%ld\t\t%s\t%.2f\t\t%.2f\t\t%.2f\t\t%s\n", st[i].id, st[i].name, st[i].objective, st[i].subjective, st[i].sum, st[i].ans); 51 } 52 53 // 从文本文件examinee.txt读入考生信息:准考证号,姓名,客观题得分,操作题得分 54 void finput(STU st[], int n) { 55 int i; 56 FILE *fin; 57 58 fin = fopen("examinee.txt", "r"); 59 if (fin == NULL) { 60 printf("fail to open file\n"); 61 exit(0); 62 } 63 64 while (!feof(fin)) { 65 for (i = 0; i < n; i++) 66 fscanf(fin, "%ld %s %f %f", &st[i].id, st[i].name, &st[i].objective, &st[i].subjective); 67 } 68 69 fclose(fin); 70 } 71 72 // 把通过考试的考生完整信息写入文件list_pass.txt 73 // 准考证号,姓名,客观题得分,操作题得分,总分,结果 74 void foutput(STU s[], int n) { 75 FILE *fout; 76 int i; 77 78 // 保存到文件 79 fout = fopen("list_pass.txt", "w"); 80 if (!fout) { 81 printf("fail to open or create list_pass.txt\n"); 82 exit(0); 83 } 84 85 fprintf(fout, "准考证号\t\t姓名\t客观题得分\t操作题得分\t总分\t\t结果\n"); 86 87 for (i = 0; i < n; i++) 88 fprintf(fout, "%ld\t\t%s\t%.2f\t\t%.2f\t\t%.2f\t\t%s\n", s[i].id, s[i].name, s[i].objective, s[i].subjective, s[i].sum, s[i].ans); 89 90 fclose(fout); 91 } 92 93 // 对考生信息进行处理:计算每位考生考试总分、结果;统计考试通过的人数 94 int process(STU st[], int n, STU st_pass[]) { 95 // 待补足 96 // ××× 97 int i,count = 0; 98 99 for (i = 0; i < n; i++){ 100 st[i].sum = st[i].objective + st[i].subjective; 101 if(st[i].sum >= 60){ 102 strcpy(st[i].ans,"pass"); 103 st_pass[count++] = st[i]; 104 } 105 else 106 strcpy(st[i].ans,"fail"); 107 } 108 109 return count; 110 }
6. 实验任务6:
1 #include <stdio.h> 2 #include <stdlib.h> 3 #include <time.h> 4 5 #define N 100 6 7 struct STU { 8 long int id; 9 char name[N]; 10 char cla[N]; 11 } st[N], lucky[N]; 12 13 void func1(void); 14 int func2(void); 15 void func3(void); 16 17 int main() { 18 int j, n; 19 func1(); 20 21 22 srand((unsigned)time(NULL)); 23 24 for (j = 0; j < 5; j++) { 25 n = func2(); 26 lucky[j] = st[n]; 27 printf("%ld\t %s\t %s\t\n", lucky[j].id, lucky[j].name, lucky[j].cla); 28 } 29 30 func3(); 31 32 getchar(); 33 34 return 0; 35 } 36 37 void func1(void) { 38 int i; 39 FILE *fp; 40 41 fp = fopen("list.txt", "r"); 42 43 if (fp == NULL) { 44 printf("Failed to open file\n"); 45 return; 46 } 47 48 i = 0; 49 while (fscanf(fp, "%ld %s %s", &st[i].id, st[i].name, st[i].cla) == 3 && i < N) { 50 ++i; 51 } 52 53 fclose(fp); 54 } 55 56 int func2(void) { 57 return rand() % 80; 58 } 59 60 void func3(void) { 61 int j; 62 FILE *fout; 63 64 fout = fopen("lucky.txt", "w"); 65 66 if (fout == NULL) { 67 printf("Failed to open file\n"); 68 return; 69 } 70 71 for (j = 0; j < 5; j++) { 72 fprintf(fout, "%ld\t %s\t %s\t\n", lucky[j].id, lucky[j].name, lucky[j].cla); 73 } 74 75 fclose(fout); 76 }
标签:printf,文件,int,void,编程,st,STU,实验,pass From: https://www.cnblogs.com/zbb07/p/18264772