一月二十四日 安卓程序开发三

实现点击按钮跳转页面功能，当点击登录时 会根据输入的用户名 密码 是否跳转页面

private Button myButtonlogin;
    private EditText metUser;
    private EditText metPassword;

    @Override

    protected void onCreate(Bundle savedInstanceState) {

        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);


        myButtonlogin=findViewById(R.id.et4);

        metUser=findViewById(R.id.et2);
        metPassword=findViewById(R.id.et3);

        myButtonlogin.setOnClickListener(this);

    }


    public void onClick(View view) {

        String ok="登录成功";
        String fail="密码或账号有误";

        String username=metUser.getText().toString();
        String password=metPassword.getText().toString();
        Intent intent=null;

        if(username.equals("20223709")&&password.equals("123456"))
        {

            ToastUtil.showMsg(MainActivity.this,ok);

            intent = new Intent(MainActivity.this, SlideActivity.class);
            startActivity(intent);

        }
        else
        {
            ToastUtil.showMsg(MainActivity.this,fail);
        }

    }