python之列表的排序、循环、合并

排序：sorted()显示临时排序

cars = ['byd','audi','gelly','qirui','chengcheng']

print(sorted(cars))

print(cars)

结果：

['audi', 'byd', 'chengcheng', 'gelly', 'qirui']

['byd', 'audi', 'gelly', 'qirui', 'chengcheng']

sort() 对列表排序并改变原序列

cars = ['byd','audi','gelly','qirui','chengcheng']

print(cars.sort())

print(cars)

结果：

None

['audi', 'byd', 'chengcheng', 'gelly', 'qirui']

注意：cars.sort()不返回结果。

使用sort()方法reverse=True 倒序排列:

cars = ['byd','audi','gelly','qirui','chengcheng']

cars.sort(reverse=True)

print(cars)

结果：

['qirui', 'gelly', 'chengcheng', 'byd', 'audi']

使用sorted()方法reverse=True 倒序排列:

cars = ['byd','audi','gelly','qirui','chengcheng']

print(sorted(cars,reverse=True))

print(cars)

结果：

['qirui', 'gelly', 'chengcheng', 'byd', 'audi']

['byd', 'audi', 'gelly', 'qirui', 'chengcheng']

反转列表（不排序仅反转列表的顺序）：reverse()

cars = ['byd','audi','gelly','qirui','chengcheng']

cars.reverse()

print(cars)

结果：

['chengcheng', 'qirui', 'gelly', 'audi', 'byd']

遍历列表：

for循环

cars = ['byd','audi','gelly','qirui','chengcheng']

for car in cars:

    print(car)

结果：

byd

audi

gelly

qirui

chengcheng

for循环和enumerate()函数   ：

cars = ['byd','audi','gelly','qirui','chengcheng']

for index,car in enumerate(cars):

    print(index,car)

结果：

0 byd

1 audi

2 gelly

3 qirui

4 chengcheng

for循环和range()函数

cars = ['byd','audi','gelly','qirui','chengcheng']

for i in range(len(cars)):

    print(i,cars[i])

结果：

0 byd

1 audi

2 gelly

3 qirui

4 chengcheng

for循环和iter()函数：

cars = ['byd','audi','gelly','qirui','chengcheng']

for car in iter(cars):

    print(car)

结果：

byd

audi

gelly

qirui

chengcheng

while循环：

cars = ['byd','audi','gelly','qirui','chengcheng']

i = 0

while i < len(cars):

    print(cars[i])

    i +=1

结果：

byd

audi

gelly

qirui

chengcheng

列表合并

加号：

cars = ['byd','audi','gelly','qirui','chengcheng']

planes = ['boyin','shenfei','chengfei']

carsAndPlanes = cars + planes

print(carsAndPlanes)

结果：

['byd', 'audi', 'gelly', 'qirui', 'chengcheng', 'boyin', 'shenfei', 'chengfei']

extend()方法：

cars = ['byd','audi','gelly','qirui','chengcheng']

planes = ['boyin','shenfei','chengfei']

# carsAndPlanes = cars.extend(planes)

cars.extend(planes)

print(cars)

结果：

['byd', 'audi', 'gelly', 'qirui', 'chengcheng', 'boyin', 'shenfei', 'chengfei']

注意：cars.extend(planes)不能返回结果。

使用切片，将一个列表插入另一个列表：

cars = ['byd','audi','gelly','qirui','chengcheng']

planes = ['boyin','shenfei','chengfei']

cars[len(cars):len(cars)]=planes

print(cars)

结果：

['byd', 'audi', 'gelly', 'qirui', 'chengcheng', 'boyin', 'shenfei', 'chengfei']

注意：语法形式如下:

list1[len(list1):len(list1)] = list2

len(list1) 代表将list2插入list1中的位置