mAP的是各个类别的AP的值的平均值
# https://blog.csdn.net/qq_36523492/article/details/108469465 计算方法选择第二种方法 the interpolation performed in all points
# 定义一个列表
lst = [3, 1, 4, 2]
# 使用sorted函数对列表进行排序，并获取原始元素在排序后列表中的索引
indexes = sorted(range(len(lst)), key=lambda x: lst[x])
print(indexes)
print(lst)
def cacluate_AP(recall_list, precision_list):
'''the interpolation performed in all points'''
assert len(recall_list) == len(precision_list)
recall_sort_index = sorted(range(len(recall_list)), key=lambda x: recall_list[x])
recall_list = [recall_list[x] for x in recall_sort_index]
precision_list = [precision_list[x] for x in recall_sort_index]
ap_value = 0
last_recall = 0
for index, recall in enumerate(recall_list):
ap_value += precision_list[index] * (recall - last_recall)
last_recall = recall
return ap_value
if __name__ == '__main__':
print(cacluate_AP([0.1, 0.3, 0.2], [1, 1, 1]))
标签：mAP,lst,index,recall,list,precision,AP,算法 From： https://www.cnblogs.com/lycsdhr/p/17914669.html