1、实验1
运行结果
2、实验2
源代码
1 #include <stdio.h>
2 #include <string.h>
3 #define N 10
4 #define M 80
5
6 typedef struct {
7 char name[M]; // 书名
8 char author[M]; // 作者
9 } Book;
10
11 int main() {
12 Book x[N] = { {"《一九八四》", "乔治.奥威尔"},
13 {"《美丽新世界》", "赫胥黎"},
14 {"《昨日的世界》", "斯蒂芬.茨威格"},
15 {"《万历十五年》", "黄仁宇"},
16 {"《一只特立独行的猪》", "王小波"},
17 {"《百年孤独》", "马尔克斯"},
18 {"《查令十字街84号》", "海莲.汉芙"},
19 {"《只是孩子》", "帕蒂.史密斯"},
20 {"《刀锋》", "毛姆"},
21 {"《沉默的大多数》", "王小波"} };
22 Book *ptr;
23 int i;
24 char author[M];
25
26 printf("所有图书信息:\n");
27 for(ptr = x;ptr < x + N;++ptr)
28 printf("%-30s%-30s\n",ptr->name,ptr->author);
29
30 printf("\n输入作者名：");
31 gets(author);
32 for(ptr = x;ptr < x + N;++ptr)
33 if(strcmp(ptr -> author, author)==0){
34 printf("%-30s%-30s\n",ptr->name,ptr->author);
35 }
36 return 0;
37 }
运行结果
3、实验3.1
源代码
1 #include<stdio.h>
2 #include<stdlib.h>
3 #define N 80
4
5 typedef struct Filminfo{
6 char name[N];
7 char director[N];
8 char region[N];
9 int year;
10 struct Filminfo *next;
11 }Film;
12
13 void output(Film *head);
14 Film *insert(Film *head,int n);
15
16 int main()
17 {
18 int n;
19 Film *head;
20
21 head = NULL;
22 printf("输入影片数目：");
23 scanf("%d",&n);
24 head = insert(head,n);
25
26 printf("\n所有影片信息如下：\n");
27 output(head);
28
29 return 0;
30 }
31
32 Film *insert(Film *head,int n)
33 {
34 int i;
35 Film *p;
36 for(i = 1;i<= n;++i){
37 p = (Film*)malloc(sizeof(Film));
38 printf("请输入第%d部影片信息：",i);
39 scanf("%s %s %s %d",p->name,p->director,p->region,&p->year);
40
41 p->next = head;
42 head = p;
43 }
44
45 return head;
46
47 }
48 void output(Film *head)
49 {
50 Film *p;
51
52 p = head;
53 while(p != NULL){
54 printf("%-20s %-20s %-20s %d\n",p->name,p->director,p->region,p->year);
55 p = p->next;
56 }
57 }
运行结果
实验3.2
源代码
1 #include<stdio.h>
2 #include<stdlib.h>
3 #define N 80
4
5 typedef struct Filminfo{
6 char name[N];
7 char director[N];
8 char region[N];
9 int year;
10 struct Filminfo *next;
11 }Film;
12
13 void output(Film *head);
14 Film *insert(Film *head,int n);
15
16 int main()
17 {
18 int n;
19 Film *head;
20 Film *p;
21
22 p = (Film*)malloc(sizeof(Film));
23 p->next = NULL;
24 head = p;
25 printf("输入影片数目：");
26 scanf("%d",&n);
27
28 head = insert(head,n);
29
30 printf("\n所有影片信息如下：\n");
31 output(head);
32
33 return 0;
34 }
35
36 Film *insert(Film *head,int n)
37 {
38 int i;
39 Film *p;
40 for(i = 1;i<= n;++i){
41 p = (Film*)malloc(sizeof(Film));
42 printf("请输入第%d部影片信息：",i);
43 scanf("%s %s %s %d",p->name,p->director,p->region,&p->year);
44
45 p->next = head->next;
46 head->next = p;
47 }
48
49 return head;
50
51 }
52 void output(Film *head)
53 {
54 Film *p;
55
56 p = head;
57 while(p != NULL){
58 printf("%-20s %-20s %-20s %d\n",p->name,p->director,p->region,p->year);
59 p = p->next;
60 }
61 }
运行结果
4、实验4
源代码
1 #include <stdio.h>
2 #define N 10
3
4 typedef struct {
5 char isbn[20]; // isbn号
6 char name[80]; // 书名
7 char author[80]; // 作者
8 double sales_price; // 售价
9 int sales_count; // 销售册数
10 } Book;
11
12 void output(Book x[], int n);
13 void sort(Book x[], int n);
14 double sales_amount(Book x[], int n);
15
16 int main() {
17 Book x[N] = {{"978-7-229-14156-1", "源泉", "安.兰德", 84, 59},
18 {"978-7-5133-5261-1", "李白来到旧金山", "谭夏阳", 48, 16},
19 {"978-7-5617-4347-8", "陌生人日记", "周怡芳", 72.6, 27},
20 {"978-7-5722-5475-8", "芯片简史", "汪波", 74.9, 49},
21 {"978-7-5046-9568-0", "数据化决策", "道格拉斯·W·哈伯德", 49, 42},
22 {"978-7-5133-4388-6", "美好时代的背后", "凯瑟琳.布", 34.5, 39},
23 {"978-7-1155-0509-5", "无穷的开始:世界进步的本源", "戴维·多伊奇", 37.5, 55},
24 {"978-7-5321-5691-7", "何为良好生活", "陈嘉映", 29.5 , 31},
25 {"978-7-5133-5109-6", "你好外星人", "英国未来出版集团", 118, 42},
26 {"978-7-2011-4617-1", "世界尽头的咖啡馆", "约翰·史崔勒基", 22.5, 44}};
27
28 printf("图书销量排名: \n");
29 sort(x, N);
30 output(x, N);
31
32 printf("\n图书销售总额: %.2f\n", sales_amount(x, N));
33
34 return 0;
35 }
36
37 // 待补足：函数output()实现
38 // ×××
39 void output(Book x[],int n)
40 {
41 double s;
42 int i;
43 printf("ISBN号\t\t\t书名\t\t\t 作者\t\t\t售价\t\t\t销售册数\n");
44 for(i = 0;i < n;i++){
45 printf("%-20s %-30s%-20s% %-10g %d\n",x[i].isbn,x[i].name,x[i].author,x[i].sales_price,x[i].sales_count);
46 }
47
48 }
49
50 // 待补足：函数sort()实现
51 // ×××
52 void sort(Book x[],int n)
53 {
54 int i,j;
55 Book t;
56 for(i = 0;i<n-1;i++){
57 for(j = i;j<=n-2;j++){
58 if(x[j+1].sales_count>x[j].sales_count){
59 t = x[j];
60 x[j] = x[j+1];
61 x[j+1] = t;
62 }
63 }
64 }
65
66 }
67
68 // 待补足：函数sales_count()实现
69 // ×××
70 double sales_amount(Book x[],int n)
71 {
72 int i;
73 double s=0;
74 for(i = 0;i < n;i++){
75 s+= x[i].sales_price*x[i].sales_count*1.0;
76 }
77 return s;
78 }
运行结果
5、实验5
源代码
1 #include<stdio.h>
2
3 typedef struct{
4 int year;
5 int month;
6 int day;
7 }Date;
8
9 void input(Date *pd);
10 int day_of_year(Date d);
11 int compare_dates(Date d1,Date d2);
12
13 void test1()
14 {
15 Date d;
16 int i;
17
18 printf("输入日期：（以形如2023-12-11这样的形式输入\n");
19 for(i = 0;i<3;++i){
20 input(&d);
21 printf("%d-%02d-%02d是这一年中的第%d天\n\n",d.year,d.month,d.day,day_of_year(d));
22 }
23 }
24
25 void test2()
26 {
27 Date Alice_birth,Bob_birth;
28 int i;
29 int ans;
30
31 printf("输入Alice和Bob出生日期：（以形如2023-12-11这样的形式输入\n");
32 for(i = 0;i<3;++i)
33 {
34 input(&Alice_birth);
35 input(&Bob_birth);
36 ans = compare_dates(Alice_birth,Bob_birth);
37
38 if(ans == 0)
39 printf("Alice和Bob一样大\n\n");
40 else if(ans == -1)
41 printf("Alice比Bob大\n\n");
42 else
43 printf("Alice比Bob小\n\n");
44
45 }
46 }
47 int main()
48 {
49 printf("测试1：输入日期，打印输出这是一年中第多少天\n");
50 test1();
51
52 printf("\n测试2：两个人年龄大小关系\n");
53 test2();
54 }
55 void input(Date *pd)
56 {
57 scanf("%d-%d-%d",&pd->year,&pd->month,&pd->day);
58 }
59 int day_of_year(Date d)
60 {
61 int s[13] = {0,31,28,31,30,31,30,31,31,30,31,30,31};
62 if(d.year%4 == 0&&d.year%400 == 0||d.year%4 == 0)
63 s[2] = 29;
64 int sum=0, i;
65 for(i = 1;i<=d.month-1;i++)
66 {
67 sum += s[i];
68 }
69 sum+=d.day;
70 return sum;
71 }
72 int compare_dates(Date d1,Date d2)
73 {
74 int ans;
75 if(d1.year<d2.year){
76 ans = -1;
77 }
78 else if(d1.year>d2.year){
79 ans = 2;
80 }
81 else{
82 if(d1.month<d2.month)
83 ans=-1;
84 else if(d1.month>d2.month)
85 ans=2;
86 else {
87 if(d1.day<d2.day)
88 ans = -1;
89 else if(d1.day>d2.day)
90 ans = 2;
91 else
92 ans = 0;
93 }
94 }
95 return ans;
96 }
运行结果
6、实验6
源代码
1 #include<stdio.h>
2 #include<string.h>
3
4 enum Role{admin,student,teacher};
5
6 typedef struct{
7 char username[20];
8 char password[20];
9 enum Role type;
10 }Account;
11
12 void output(Account x[],int n);
13
14 int main()
15 {
16 Account x[]={{"A1001","123456",student},
17 {"A1002","123abcdef",student},
18 {"A1009","xyz12121",student},
19 {"X1009","9213071x",admin},
20 {"C11553","129dfg32k",teacher},
21 {"x3005","9221kfmg917",student}};
22 int n;
23 n = sizeof(x)/sizeof(Account);
24 output(x,n);
25
26 return 0;
27 }
28 void output(Account x[],int n)
29 {
30 int i,j,k;
31 for(i = 0;i<n;i++){
32 printf("%s\t",x[i].username);
33 j = strlen(x[i].password);
34
35 for(k = 0;k<j;k++)
36 printf("*");
37 if(j<7){
38 printf("\t\t");
39 }
40 else{
41 printf("\t");
42 }
43 switch(x[i].type){
44 case admin:printf("admin");break;
45 case student:printf("student");break;
46 case teacher:printf("teacher");break;
47 }
48 printf("\n");
49 }
50 }
运行结果
标签：head,int,编程,C语言,char,枚举,printf,output,Film From： https://www.cnblogs.com/liyushi0818/p/17894784.html