需求

两个0-10000的数组，循环遍历两个数组，获取两个元素，打印出乘积为56213的所有元素

Python实现

import datetime
    s = datetime.datetime.now()
    for i in range(10000):
        for j in range(10000):
            if i * j == 56213:
                print(f"{i} * {j} = {i * j}")
    print(datetime.datetime.now() - s)
# 结果
# 67 * 839 = 56213
# 839 * 67 = 56213
# 0:00:09.320285

Go实现

package main

import (
	"fmt"
	"time"
)

func generateList(n int) []int {
	list := make([]int, n+1)
	for i := 0; i <= n; i++ {
		list[i] = i
	}
	return list
}

func main() {
	start := time.Now()
	list1 := generateList(10000)
	list2 := generateList(10000)

	for _, n1 := range list1 {
		for _, n2 := range list2 {
			if n1*n2 == 56213 {
				fmt.Printf("%d * %d = 56213 \n", n1, n2)
			}
		}
	}
	fmt.Println(time.Now().Sub(start))
}
# 结果
# 67 * 839 = 56213 
# 839 * 67 = 56213 
# 66.757ms