assume cs:code
data segment
db 10 dup (0)
code segment
start:
mov ax,12666
mov bx,data
mov ds,bx
mov si,0
call dtoc
mov dh,8
mov dl,3
mov cl,2
call show_str
mov ax,4c00h
int 21h
dtoc: push ax
push bx
push cx
push dx
push si
push di
mov bx,10
mov dx,0
mov di,0
change: div bx
add dx,30h
push dx
inc di
mov cx,ax
jcxz ok
mov dx,0
jmp short change
ok:mov cx,di
s:pop [si]
inc si
loop s
pop di
pop si
pop dx
pop cx
pop bx
pop ax
ret
show_str:
push ax
push cx
push es
push si
push di
mov di,0
mov ah,0
mov al,160
mul dh
add di,ax
mov ah,0
mov al,2
mul dl
add di,ax
mov ax,0b800h
mov es,ax
mov ah,cl
chang:mov cl,[si]
jcxz ol
mov al,[si]
mov es:[di],ax
inc si
add di,2
jmp short chang
ol:pop di
pop si
pop es
pop cx
pop ax
ret
code ends
end start
标签：10.3,di,汇编语言,mov,pop,si,push,ax,王爽 From： https://www.cnblogs.com/hellomydaughter/p/17527363.html