1. 项目启动报错:Failed to start bean 'documentationPluginsBootstrapper'
度娘解释:swagger 的匹配模式进行调整导致,导致默认的匹配默认在spring boot中不会使用,导致报错。
处理方式:(不建议降低spring boot 版本,调整太大了)
spring:
mvc:
pathmatch:
matching-strategy: ant_path_matcher
2. spring gateway路由出现503
是因为在Spring Cloud 2020
版本以后,默认移除了对Netflix
的依赖,其中就包括Ribbon
,官方默认推荐使用Spring Cloud Loadbalancer
正式替换Ribbon
,并成为了Spring Cloud
负载均衡器的唯一实现,只需要将含有这个过滤器的依赖进行导入就行了
<dependency>
<groupId>org.springframework.cloud</groupId>
<artifactId>spring-cloud-loadbalancer</artifactId>
</dependency>
3. spring gateway路由出现404
配置如下,我期望路径包含/ebook/**
时,能向service-book
服务发请求,进入指定方法体。
spring:
cloud:
gateway:
routes:
- id: ebook
uri: lb://service-ebook #用百度做转发测试 http://www.baidu.com
predicates: # 断言
- Path=/ebook/**
实际情况报错:
报错原因:
gateway,获取到指定请求后返回请求的路径为http://127.0.0.1:8890/ebook/auth/code
,但实际上路径应为/auth/code
,没有/ebook
处理方式:
spring:
cloud:
gateway:
default-filters:
- StripPrefix=1
规则:
StripPrefix=1 :/ebbok/auth/code -> /auth/code
StripPrefix=2 :/ebbok/auth/code -> /code
......
4. List 转为 Map
public void test4() {
Student stu1 = new Student("张三", 23);
Student stu2 = new Student("李四", 24);
Student stu3 = new Student("王五", 25);
Student stu4 = new Student("赵六", 23);
Student stu5 = new Student("前七", 25);
List<Student> strList = new ArrayList<>();
Collections.addAll(strList, stu1, stu2, stu3, stu4,stu5);
// 1.根据age作为key,name作为value转map(age相同时前面覆盖后面的数据)
Map<Integer, String> collect = strList.stream().collect(Collectors.toMap(Student::getAge, Student::getName, (key1,key2) -> key1 ));
for (Map.Entry<Integer, String> integerStudentEntry : collect.entrySet()) {
System.out.println(integerStudentEntry.getKey() + ":" + String.valueOf(integerStudentEntry.getValue()));
}
// 2.根据age作为key,student对象作为value转map(age相同时前面覆盖后面的数据)
Map<Integer, Student> collectStu = strList.stream().collect(Collectors.toMap(Student::getAge, Function.identity(), (key1, key2) -> key2));
for (Map.Entry<Integer, Student> integerStudentEntry : collectStu.entrySet()) {
System.out.println(integerStudentEntry.getKey() + "::" + String.valueOf(integerStudentEntry.getValue()));
}
// 3.根据age作为key,student对象作为value分组转map(age相同时前面覆盖后面的数据)
Map<Integer, List<Student>> listMap = strList.stream().collect(Collectors.groupingBy(Student::getAge));
for (Map.Entry<Integer, List<Student>> integerStudentEntry : listMap.entrySet()) {
System.out.println(integerStudentEntry.getKey() + "::" + String.valueOf(integerStudentEntry.getValue()));
}
}
标签:Map,code,JAVA,草稿,spring,Student,new,integerStudentEntry
From: https://www.cnblogs.com/zz-1q/p/17375031.html