import re def removeComments(string): pattern = r"(\".*?\"|\'.*?\')|((?s)/\*.*?\*/)|(//[^\r\n]*$)" regex = re.compile(pattern, re.MULTILINE | re.DOTALL) def _replacer(match): if match.group(2) is not None: return " " else: return match.group(1) or match.group(3) return regex.sub(_replacer, string) with open("0.txt", "r", encoding="utf-8") as f: line = f.readline(); while line: line = line.strip() # 去掉换行符"\n res = removeComments(line) if(res.isspace()==False and len(res)!=0): print(res) line=f.readline()
1、0.txt可以替换为你需要替换的智能合约源代码文件。
2、我是一句代码一句代码的处理,将代码通过正则表达式是否满足三种注释的原则。其次,判断该句话是不是为空行。最终进行输出答案。
标签:空行,group,Python,res,代码,Solidity,re,line,match From: https://www.cnblogs.com/Alei777/p/17146123.html