K 正方形(SDUT 2444)
import java.lang.reflect.Array;
import java.util.*;
public class Main {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
int t = sc.nextInt();
node s[] = new node[2000];
// System.out.println(55);
for (int k = 0; k < t; k++) {
for (int i = 0; i < 4; i++) {
s[i] = new node();
s[i].x = sc.nextInt();
s[i].y = sc.nextInt();
// System.out.println(s[i].x + " " + s[i].y);
}
s[4] = new node();
s[4].x = s[0].x;
s[4].y = s[0].y;
Sum p = new Sum(s);
if (p.getAns() == 1) {
System.out.print("YES\n");
} else
System.out.print("NO\n");
}
sc.close();
}
}
class node {
int x;
int y;
}
class Sum {
node s[] = new node[200];
Sum(node s[]) {
this.s = s;
}
int f1() {
int f = 1;
for (int i = 0; i < 3; i++) {
int x = s[i].x - s[i + 1].x;
int y = s[i].y - s[i + 1].y;
int z = s[i + 1].x - s[i + 2].x;
int w = s[i + 1].y - s[i + 2].y;
if (x * x + y * y != z * z + w * w) {
f = 0;
break;
}
}
return f;
}
int f2() {
int f = 1;
for (int i = 0; i < 3; i++) {
int x = (s[i + 1].x - s[i].x) * (s[i + 2].x - s[i + 1].x);
int y = (s[i + 1].y - s[i].y) * (s[i + 2].y - s[i + 1].y);
if (x != -y) {
f = 0;
break;
}
}
return f;
}
int getAns() {
int flag1 = f1();
int flag2 = f2();
if (flag1 == 1 && flag2 == 1)
return 1;
else
return 0;
}
}
相似三角形(SDUT 2562)
import java.util.Arrays;
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
int a[] = new int[10];
while (sc.hasNext()) {
for (int i = 0; i < 6; i++) {
a[i] = sc.nextInt();
}
Node p = new Node(a);
int ans = p.getAns();
if (ans == 1)
System.out.println("YES");
else
System.out.println("NO");
}
}
}
class Node {
int a[] = new int[10];
Node(int a[]) {
this.a = a;
}
int getOk() {
int f1 = 0;
int f2 = 0;
if (a[0] + a[1] > a[2] && a[0] + a[2] > a[1] && a[1] + a[2] > a[0])
f1 = 1;
if (a[3] + a[4] > a[5] && a[3] + a[5] > a[4] && a[4] + a[5] > a[3])
f2 = 1;
if (f1 == 1 && f2 == 1)
return 1;
else
return 0;
}
int getAns() {
if (getOk() == 1) {
int f = 0;
Arrays.sort(a, 0, 3);
Arrays.sort(a, 3, 6);
if ((a[0] * a[4] == a[1] * a[3]) && (a[0] * a[5] == a[2] * a[3]) && (a[1] * a[5] == a[2] * a[4]))
f = 1;
return f;
} else
return 0;
}
}
N 手机键盘 (SDUT 2618)
import java.util.Arrays;
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
String s[] = new String[10];
s[2] = "abc0";s[3] = "def0";s[4] = "ghi0"; s[5] = "jkl0";
s[6] = "mno0"; s[7] = "pqrs"; s[8] ="tuv0";s[9] = "wxyz";
String str;
while (sc.hasNext()) {
str = sc.nextLine();
Node p;
p = new Node(s,str);
int ans = p.getAns();
System.out.println(ans);
}
}
}
class Node {
String str;
String s[] = new String[10];
Node(String s[], String str) {
this.str = str;
this.s = s;
}
int getAns()
{
int ans = 0,f = 0;
int flag = 0;
int i,j,k;
int len = str.length();
for( i = 0; i < len; i ++)
{
flag = 0;
for( j = 2; j <= 9; j ++)
{
for( k = 0; k < 4; k ++)
{
if(i == 0)
{
if(s[j].charAt(k) == str.charAt(i)) {
ans += k + 1;
f = j;
flag = 1;
break;
}
}
else {
if(s[j].charAt(k) == str.charAt(i))
{
if(f == j)ans += k + 3;
else {ans += k + 1;f = j;}
flag = 1;
break;
}
}
}
if(flag == 1) break;
}
}
return ans;
}
}
2-2 Time类的定义 (SDUT 2669)
import java.util.Arrays;
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
int H,M,S;
H = sc.nextInt();
M = sc.nextInt();
S = sc.nextInt();
Time t = new Time(H,M,S);
t.prit();
}
}
class Time
{
int h,m,s;
Time(int H, int M, int S)
{
h = H;
m = M;
s = S;
}
void setH()
{
if(h > 12 || h < 0) h = 12;
}
void setM()
{
if(m > 60 || m < 0) m = 0;
}
void setS()
{
if(s > 60 || s < 0) s = 0;
}
void prit()
{
setH();setM();setS();
System.out.printf("%02d:%02d:%02d\n", h,m,s);
}
}
标签:Java,String,int,System,面向对象,sc,new,Scanner From: https://blog.51cto.com/u_15965659/6056634