python归并排序

1. 采用了分治法，把序列不断的等分序列，最后分成一个之后，再把它两两合并叠加起来，利用了扑克牌两个正序序列进行排序合并
2. 时间复杂度 nlogn
3. 代码

def merge_sort(lists):
    if len(lists) <= 1:
        return lists
    middle = len(lists) // 2
    left = merge_sort(lists[:middle])
    right = merge_sort(lists[middle:])
    return merge(left, right)


def merge(left: list, right: list):
    c = []
    i = j = 0
    while i < len(left) and j < len(right):
        if left[i] < right[j]:
            c.append(left[i])
            i += 1
        else:
            c.append(right[j])
            j += 1
    if i == len(left):
        for i in right[j:]:
            c.append(i)
    else:
        for i in left[i:]:
            c.append(i)
    return c


if __name__ == '__main__':
    list = [1, 5, 2, 3, 8, 9, 10, 11, 12, 14, 14, 7]
    print(merge_sort(list))